5x-0.24x^2-17=0

Solution for 5x-0.24x^2-17=0 equation:

5x-0.24x^2-17=0

a = -0.24; b = 5; c = -17;
Δ = b2-4ac
Δ = 52-4·(-0.24)·(-17)
Δ = 8.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{8.68}}{2*-0.24}=\frac{-5-\sqrt{8.68}}{-0.48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{8.68}}{2*-0.24}=\frac{-5+\sqrt{8.68}}{-0.48}
$